Metadata-Version: 2.1
Name: regxdev
Version: 1.0.0
Summary: This package is made especially for developers or web scrapers for saving time while scraping the information.
Home-page: https://github.com/mr-elliot/Regx-Dev/
Author: Sanjay kumar J
Author-email: sanjaykumarj222@gmail.com
License: UNKNOWN
Project-URL: Bug Reports, https://github.com/mr-elliot/Regx-Dev/issues
Project-URL: Source, https://github.com/mr-elliot/Regx-Dev/
Description: # regxdev #
        
        This package is made to developers for saving them time while playing in scraping the information.
        
        ## Feature's of this project
        
        * Find's any format of phone number irrespective of the country.
        * Can find links from the string.
        * Can extract the mail id from a string.
        * Removes any links from the string.
        * Return's the index of the matching word present in the string as a list.
        * Can replace any word provided with a new word.
        
        # How to install and use it.
        
        `pip install regxdev`
        
        ` from regxdev import regxdev as rd `
        
        * For finding phone number from the string you passed.
        
          ` result = rd.phone_finder("PASS THE STRING CONTAINING NUMBEERS") ` returns list of phone numbers 
        
            Note: This method works only if numbers start with the prefix '+' and not containing parentheses.
        
        * For finding links.
        
          ` result = rd.link_finder("PASS THE STRING") ` returns list of links in the string.
        
        * For extracting mail ids.
          
          ` result = rd.mail_extractor("PASS THE STRING") `
        
        * For removing links.
        
          ` result = rd.link_remover("PASS THE STRING") `
        
        * This returns a list of tuples that is the index of a matched word you were searching for in the list.
        
          ` result = rd.word_finder("WORD TO BE FOUND", "PASS THE STRING") `
          
          For example: when you run the above line you get output similar to ` result = [(2, 5), (11, 14)] ` each item are tuples, which contains the start index and end index of the word. you can use this tuple and by slicing the string you will have the word.
        
        * To replace any word from the string irrespective of length.
          
          ` result = rd.word_replacer("WORD TO REPLACE", "WORD TO BE REPLACED FOR", "PASS THE STRING") `
        
          This returns a new string with a replaced character.
        
        
        Feel free to contact me if you have any problem or looking for any new implementation or any idea/suggestion.
        
        
Keywords: re,phone-scrape,finding
Platform: UNKNOWN
Classifier: Programming Language :: Python :: 3
Classifier: License :: OSI Approved :: MIT License
Classifier: Operating System :: OS Independent
Requires-Python: >=3.6
Description-Content-Type: text/markdown
